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authorRussell Keith-Magee <russell@keith-magee.com>2008-09-14 08:58:16 +0000
committerRussell Keith-Magee <russell@keith-magee.com>2008-09-14 08:58:16 +0000
commite600d00b44348d860d2847c4697ad9b21e1824d2 (patch)
tree1eac49bc337943dc2049fe5c35ef885536f64727 /docs
parent7ab3285f64322346a763a231ddabb934102b6b50 (diff)
Fixed #9067: Added a note that you can register a model with the admin without providing a ModelAdmin object. Thanks to Rob Hudson for the suggestion.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@9024 bcc190cf-cafb-0310-a4f2-bffc1f526a37
Diffstat (limited to 'docs')
-rw-r--r--docs/ref/contrib/admin.txt14
1 files changed, 14 insertions, 0 deletions
diff --git a/docs/ref/contrib/admin.txt b/docs/ref/contrib/admin.txt
index 0c2b34509f..19e836fd3f 100644
--- a/docs/ref/contrib/admin.txt
+++ b/docs/ref/contrib/admin.txt
@@ -50,6 +50,20 @@ Let's take a look at a very simple example the ``ModelAdmin``::
pass
admin.site.register(Author, AuthorAdmin)
+.. admonition:: Do you need a ``ModelAdmin`` object at all?
+
+ In the preceding example, the ``ModelAdmin`` class doesn't define any
+ custom values (yet). As a result, the default admin interface will be
+ provided. If you are happy with the default admin interface, you don't
+ need to define a ``ModelAdmin`` object at all -- you can register the
+ model class without providing a ``ModelAdmin`` description. The
+ preceding example could be simplified to::
+
+ from django.contrib import admin
+ from myproject.myapp.models import Author
+
+ admin.site.register(Author)
+
``ModelAdmin`` Options
----------------------