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authorTim Graham <timograham@gmail.com>2013-07-11 11:06:34 -0400
committerTim Graham <timograham@gmail.com>2013-07-11 11:07:59 -0400
commitc278d81da40430f401cb7ce24f6bc603c40f3de7 (patch)
tree883c58ee83f827a3f871ebdb4db777d6545aeada /docs
parent2f9378223d0c92447e2529d5eeaad7d301b78b84 (diff)
[1.5.x] Fixed #20730 -- Fixed "Programmatically creating permissions" error.
Thanks glarrain for the report. Backport of 684a606a4e from master
Diffstat (limited to 'docs')
-rw-r--r--docs/topics/auth/default.txt3
1 files changed, 2 insertions, 1 deletions
diff --git a/docs/topics/auth/default.txt b/docs/topics/auth/default.txt
index 4072c51771..3234b53e55 100644
--- a/docs/topics/auth/default.txt
+++ b/docs/topics/auth/default.txt
@@ -234,10 +234,11 @@ a model's ``Meta`` class, you can also create permissions directly. For
example, you can create the ``can_publish`` permission for a ``BlogPost`` model
in ``myapp``::
+ from myapp.models import BlogPost
from django.contrib.auth.models import Group, Permission
from django.contrib.contenttypes.models import ContentType
- content_type = ContentType.objects.get(app_label='myapp', model='BlogPost')
+ content_type = ContentType.objects.get_for_model(BlogPost)
permission = Permission.objects.create(codename='can_publish',
name='Can Publish Posts',
content_type=content_type)